简单链表输入输出：

#include 
     
      #include 
      
       using namespace std;int a[100]; struct poi{    int now;    poi *next;};int main(){    poi *start;    poi *now;    now=NULL;     start=now;    int i=0;    poi *noww;    while (++i<=10)    {        noww=new poi;        noww->next=now;        start=noww;        now=noww;        scanf("%d",&now->now);    }    printf("%d\n",start->now);    now=start;    while (now!=NULL)    {        printf("%d\n",now->now);        now=now->next;    }}